Cara mudah mencari limit yang ada akar pangkat tiga tanpa L’Hospital


\lim\limits_{x \rightarrow \infty}\frac{\sqrt[3]{x}-2}{x-8}

misalkan x = y^3

Jika x \rightarrow 8  maka y^3 \rightarrow 8 .

Akibatnya y \rightarrow \sqrt[3]{8}  atau y \rightarrow 2

Soal diubah menjadi

\lim\limits_{x \rightarrow 8}\frac{\sqrt[3]{x}-2}{x-8} = \lim\limits_{y \rightarrow 2}\frac{y-2}{y^3-8}

Diselesaikan dengan teknik horner, diperoleh hasilnya yaitu \frac{1}{12}.

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